81 lines
2.8 KiB
C++
81 lines
2.8 KiB
C++
/********************************************************
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* ██████╗ ██████╗████████╗██╗
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* ██╔════╝ ██╔════╝╚══██╔══╝██║
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* ██║ ███╗██║ ██║ ██║
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* ██║ ██║██║ ██║ ██║
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* ╚██████╔╝╚██████╗ ██║ ███████╗
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* ╚═════╝ ╚═════╝ ╚═╝ ╚══════╝
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* Geophysical Computational Tools & Library (GCTL)
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*
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* Copyright (c) 2022 Yi Zhang (yizhang-geo@zju.edu.cn)
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*
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* GCTL is distributed under a dual licensing scheme. You can redistribute
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* it and/or modify it under the terms of the GNU Lesser General Public
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* License as published by the Free Software Foundation, either version 2
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* of the License, or (at your option) any later version. You should have
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* received a copy of the GNU Lesser General Public License along with this
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* program. If not, see <http://www.gnu.org/licenses/>.
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*
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* If the terms and conditions of the LGPL v.2. would prevent you from using
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* the GCTL, please consider the option to obtain a commercial license for a
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* fee. These licenses are offered by the GCTL's original author. As a rule,
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* licenses are provided "as-is", unlimited in time for a one time fee. Please
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* send corresponding requests to: yizhang-geo@zju.edu.cn. Please do not forget
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* to include some description of your company and the realm of its activities.
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* Also add information on how to contact you by electronic and paper mail.
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******************************************************/
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#include "gctl/core.h"
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#include "gctl/algorithm.h"
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int main(int argc, char const *argv[])
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{
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gctl::array<double> all_data(1000);
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gctl::random(all_data, 0.0, 2.0);
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// 计算均值和方差
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double mean = 0, stddev = 0;
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for (int i = 0; i < all_data.size(); i++)
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{
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mean += all_data[i];
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}
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mean /= all_data.size();
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for (int i = 0; i < all_data.size(); i++)
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{
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stddev += pow(all_data[i] - mean, 2.0);
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}
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stddev = sqrt(stddev/all_data.size());
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std::cout << "mean = " << mean << ", stddev = " << stddev << std::endl;
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// 计算前900个的均值和方差 然后动态计算最后100次
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mean = 0;
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stddev = 0;
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for (int i = 0; i < 900; i++)
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{
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mean += all_data[i];
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}
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mean /= 900;
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for (int i = 0; i < 900; i++)
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{
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stddev += pow(all_data[i] - mean, 2.0);
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}
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stddev = sqrt(stddev/900);
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std::cout << "mean = " << mean << ", stddev = " << stddev << std::endl;
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double new_mean;
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int count = 900;
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for (int i = 0; i < 100; i++)
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{
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stddev = gctl::dynamic_stddev(stddev, count, mean, all_data[900 + i], new_mean);
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mean = new_mean;
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std::cout << i << " mean = " << mean << ", stddev = " << stddev << std::endl;
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count++;
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}
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return 0;
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} |