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@ -18,4 +18,5 @@ add_example(ex5 ON)
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add_example(ex6 ON)
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add_example(ex6 ON)
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add_example(ex7 ON)
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add_example(ex7 ON)
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add_example(ex8 ON)
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add_example(ex8 ON)
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add_example(ex9 ON)
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add_example(ex9 ON)
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add_example(ex10 ON)
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64
example/ex10.cpp
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64
example/ex10.cpp
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@ -0,0 +1,64 @@
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/********************************************************
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* ██████╗ ██████╗████████╗██╗
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* ██╔════╝ ██╔════╝╚══██╔══╝██║
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* ██║ ███╗██║ ██║ ██║
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* ██║ ██║██║ ██║ ██║
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* ╚██████╔╝╚██████╗ ██║ ███████╗
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* ╚═════╝ ╚═════╝ ╚═╝ ╚══════╝
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* Geophysical Computational Tools & Library (GCTL)
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*
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* Copyright (c) 2022 Yi Zhang (yizhang-geo@zju.edu.cn)
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*
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* GCTL is distributed under a dual licensing scheme. You can redistribute
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* it and/or modify it under the terms of the GNU Lesser General Public
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* License as published by the Free Software Foundation, either version 2
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* of the License, or (at your option) any later version. You should have
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* received a copy of the GNU Lesser General Public License along with this
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* program. If not, see <http://www.gnu.org/licenses/>.
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*
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* If the terms and conditions of the LGPL v.2. would prevent you from using
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* the GCTL, please consider the option to obtain a commercial license for a
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* fee. These licenses are offered by the GCTL's original author. As a rule,
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* licenses are provided "as-is", unlimited in time for a one time fee. Please
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* send corresponding requests to: yizhang-geo@zju.edu.cn. Please do not forget
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* to include some description of your company and the realm of its activities.
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* Also add information on how to contact you by electronic and paper mail.
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******************************************************/
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#include "gctl/core.h"
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#include "gctl/algorithm.h"
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#include "../lib/optimization.h"
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#include "iostream"
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#include "iomanip"
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using std::cout;
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using std::endl;
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using std::setw;
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int main(int argc, char const *argv[])
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{
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gctl::matrix<double> A(4, 3);
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for (int i = 0; i < A.row_size(); i++)
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{
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for (int j = 0; j < A.col_size(); j++)
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{
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A[i][j] = 3*(i+1) + j - 2;
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}
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}
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A[3][1] = 1;
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gctl::array<double> x(3), y(3), m(3);
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x.random_float(-1.0, 1.0, gctl::RdUniform, 452);
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gctl::matvec(y, A, x);
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cout<<"A(" << A.row_size() << ", " << A.col_size() << ") = " <<endl;
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A.show();
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gctl::svd svdd;
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svdd.decompose(A);
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svdd.solve(y, m);
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cout << "x = "; x.show();
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cout << "m = "; m.show();
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return 0;
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}
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@ -199,4 +199,27 @@ void gctl::svd::decompose(const matrix<double> &src_mat)
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else break;
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else break;
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}
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}
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return;
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return;
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}
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// solve for x in form Ax = b. A is the original input matrix.
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// Note: b is modified in-place for row permutations
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void gctl::svd::solve(const array<double>& b, array<double> &x)
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{
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if (b.empty())
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{
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throw domain_error("Invalid target vector. From gctl::svd::solve(...)");
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}
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x.resize(b.size());
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array<double> t(K, 0.0);
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matvec(t, U, b, NoTrans);
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for (size_t i = 0; i < K; i++)
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{
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t[i] *= 1.0/S[i];
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}
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matvec(x, V, t, Trans);
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return;
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}
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}
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@ -62,6 +62,14 @@ namespace gctl
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void decompose(const matrix<double> &src_mat);
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void decompose(const matrix<double> &src_mat);
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/**
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* @brief Solve for x in form Ax = b. A is the original input matrix.
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*
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* @param b Right hang term of the linear system.
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* @param x Return solution.
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*/
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void solve(const array<double>& b, array<double> &x);
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protected:
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protected:
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int maxi_iteration, K;
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int maxi_iteration, K;
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double epsilon;
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double epsilon;
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