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CircleCI Docs
2025-01-09 21:56:20 +00:00
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@@ -421,3 +421,77 @@ the most opportunity to optimize the computation graph:
# Compiling the outer function is good to do as it will likely
# be faster even though the inner functions are compiled
fun = mx.compile(outer)
.. _shapeless_compile:
Shapeless Compilation
---------------------
When the shape of an input to a compiled function changes, the function is
recompiled. You can compile a function once and run it on inputs with
variable shapes by specifying ``shapeless=True`` to :func:`compile`. In this
case changes to the shapes of the inputs do not cause the function to be
recompiled.
.. code-block:: python
def fun(x, y):
return mx.abs(x + y)
compiled_fun = mx.compile(fun, shapeless=True)
x = mx.array(1.0)
y = mx.array(-2.0)
# Firt call compiles the function
print(compiled_fun(x, y))
# Second call with different shapes
# does not recompile the function
x = mx.array([1.0, -6.0])
y = mx.array([-2.0, 3.0])
print(compiled_fun(x, y))
Use shapeless compilations carefully. Since compilation is not triggered when
shapes change, any graphs which are conditional on the input shapes will not
work as expected. Shape-dependent computations are common and sometimes subtle
to detect. For example:
.. code-block:: python
def fun(x):
return x.reshape(x.shape[0] * x.shape[1], -1)
compiled_fun = mx.compile(fun, shapeless=True)
x = mx.random.uniform(shape=(2, 3, 4))
out = compiled_fun(x)
x = mx.random.uniform(shape=(5, 5, 3))
# Error, can't reshape (5, 5, 3) to (6, -1)
out = compiled_fun(x)
The second call to the ``compiled_fun`` fails because of the call to
:func:`reshape` which uses the static shape of ``x`` in the first call. We can
fix this by using :func:`flatten` to avoid hardcoding the shape of ``x``:
.. code-block:: python
def fun(x):
return x.flatten(0, 1)
compiled_fun = mx.compile(fun, shapeless=True)
x = mx.random.uniform(shape=(2, 3, 4))
out = compiled_fun(x)
x = mx.random.uniform(shape=(5, 5, 3))
# Ok
out = compiled_fun(x)