Add spack edit -c option to edit commands.
This commit is contained in:
parent
ff546358f3
commit
319b37af0e
@ -27,9 +27,10 @@
|
||||
from contextlib import closing
|
||||
|
||||
import llnl.util.tty as tty
|
||||
from llnl.util.filesystem import mkdirp
|
||||
from llnl.util.filesystem import mkdirp, join_path
|
||||
|
||||
import spack
|
||||
import spack.cmd
|
||||
from spack.util.naming import mod_to_class
|
||||
|
||||
description = "Open package files in $EDITOR"
|
||||
@ -57,6 +58,9 @@ def setup_parser(subparser):
|
||||
subparser.add_argument(
|
||||
'-f', '--force', dest='force', action='store_true',
|
||||
help="Open a new file in $EDITOR even if package doesn't exist.")
|
||||
subparser.add_argument(
|
||||
'-c', '--command', dest='edit_command', action='store_true',
|
||||
help="Edit the command with the supplied name instead of a package.")
|
||||
subparser.add_argument(
|
||||
'name', nargs='?', default=None, help="name of package to edit")
|
||||
|
||||
@ -64,7 +68,16 @@ def setup_parser(subparser):
|
||||
def edit(parser, args):
|
||||
name = args.name
|
||||
|
||||
# By default open the directory where packages live.
|
||||
if args.edit_command:
|
||||
if not name:
|
||||
path = spack.cmd.command_path
|
||||
else:
|
||||
path = join_path(spack.cmd.command_path, name + ".py")
|
||||
if not os.path.exists(path):
|
||||
tty.die("No command named '%s'." % name)
|
||||
|
||||
else:
|
||||
# By default open the directory where packages or commands live.
|
||||
if not name:
|
||||
path = spack.packages_path
|
||||
else:
|
||||
|
Loading…
Reference in New Issue
Block a user