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spack ci generate: allow use of --output-file <file> with wo/ preceding path (#17275)

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eugeneswalker 2020-06-26 11:18:29 -07:00 committed by GitHub
parent 1602b7a561
commit d8da1e6dbc
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1 changed files with 4 additions and 4 deletions
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8
lib/spack/spack/cmd/ci.py
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@ -38,7 +38,7 @@ def setup_parser(subparser):
generate = subparsers.add_parser('generate', help=ci_generate.__doc__)
generate.add_argument(
'--output-file', default=None,
help="Absolute path to file where generated jobs file should be " +
help="Path to file where generated jobs file should be " +
"written. The default is .gitlab-ci.yml in the root of the " +
"repository.")
generate.add_argument(
@ -88,10 +88,10 @@ def ci_generate(args):
use_dependencies = args.dependencies
if not output_file:
gen_ci_dir = os.getcwd()
output_file = os.path.join(gen_ci_dir, '.gitlab-ci.yml')
output_file = os.path.abspath(".gitlab-ci.yml")
else:
gen_ci_dir = os.path.dirname(output_file)
output_file_path = os.path.abspath(output_file)
gen_ci_dir = os.path.dirname(output_file_path)
if not os.path.exists(gen_ci_dir):
os.makedirs(gen_ci_dir)